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The PLANCK
RELATION and the MASS OF THE PHOTON
by
Miles Mathis
The Planck
relation (or PlanckEinstein Relation) is just an equation
relating the energy of a moving particle to its frequency, via
the de Broglie wave. The particle does not have to be a photon;
it can be any quantum, like an electron.
E=hf
Where h is Planck's constant. However, since I have shown
that Planck's constant is hiding the mass of the photon, we may
now unwind this equation, finding much more information buried
beneath it. Using simple mechanical postulates, I have calculated
that the mass of the infrared photon is h/2,400. To find this, I
simply used G to scale down from the proton mass. You can also
use the Dalton, 1821, to find this same mass. Simply cube the
Dalton and invert it. The Dalton is an outcome of spin mechanics,
and the photon is three levels below the proton and two levels
below the electron. Using the Dalton, you will get 2,400, but
using G will require you multiply by an additional 2.5. This is
because G is a scale for size, not mass, and the density of the
photon is not equal to the density of the proton.
If we
apply these new findings to the Planck relation, we see that the
relation is between mass and energy, just like Einstein's
equation E=mc^{2}. And this means that the dimensions of
h have been hiding something. Planck's constant is given complex
dimensions to account for the transform to f, but if h
contains a photon mass, then we are really transforming E into a
mass, a frequency, and x:
E = xm_{c} f
Let us apply the equation to the photon itself, to begin
with. In that case
x = cλ E = m_{c} cλf cλ
= 2,400 λ = 8 x 10^{6}m
Which is the infrared
photon I chose to begin with.
E = m_{c} cλf
= mc^{2}
Yes, Planck's relation is just a
restatement of Einstein's equation, but the two together are used
to hide the mass of the photon. The standard model forbids you
from applying Einstein's equation to the photon, or from seeking
this photon mass in the Planck relation. Why? Because that would
mess up their gauge math.
We can do the same thing for the
electron:
E = ½ m_{e} vλf = ½ m_{e}v^{2} h
= ½ m_{e} vλ
The mass of the electron is 3.3 x
10^{6} times greater than the mass of the infrared
photon, so vλ must be much less than cλ.
vλ = 2h/m =
.00146
In the famous DavissonGermer experiment of 1927,
electrons were fired at a crystalline nickel target. We are told
they were slowmoving, but are not given a velocity. We may now
calculate it directly. The wavelength was measured from the
experiment to be .165nm, which makes the velocity of the
electrons 8.8 x 10^{6}m/s or .03c. Not so slow.
I
think you really have to ask why the standard model refuses to
write the equations this way. Why do they refuse to show the
simple mechanics and math I have shown here? The answer, again,
is to save their gauge math, a math that already contains its own
fields and symmetries. They have tried to match nature to the
symmetries, but that has never worked for them. I would suggest
they try to match their math to nature, rather than nature to
math. They have already had to break their gauge symmetries to
match experiments. If the gauge symmetries require breaking, then
the matrices must have been wrong to start with. And if that is
so, then the gauge math should be ditched as a whole.
I
cannot fathom why physicists are so in love with tools that do
not work. It is as if they have a pathological obsession for the
patches themselves. The modern physicist is like a carpenter in
love with a golden hammer whose handle is cracked. The gold is
too soft to work, and the head flies of with every swing; but the
carpenter must use it and nothing else, since he has convinced
himself that the shine of it is what generates his business.
Addendum [February 2010]: we can use the above math to
discover what quantum Planck's constant is really hiding. I have
said that Planck's constant is hiding the mass of the photon, but
since photons have different energies, we may ask which photon it
is hiding. Well, we can see from above that h = mcλ. So we just
make cλ = 1, and we will have h = m, you see. The photon that
has a wavelength of 1/c is a photon with a wavelength of 3.3 x
10^{9}m, which is an Xray. Since current physics is
using h as the quantum of action, they must be using the Xray as
a quantum. This is not logical. It is much more logical to use
the charge photon as a quantum. We should be using the infrared
photon as the field quantum, not the Xray.
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